document.write( "Question 704682: ln(x)+ln(x-8)=5\r
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document.write( "I'm supposed to solve for x and I'm lost. I did it the way I thought it should be done but I got it wrong. \n" );
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Algebra.Com's Answer #434232 by nerdybill(7384) You can put this solution on YOUR website! ln(x)+ln(x-8)=5 \n" ); document.write( "ln((x)(x-8)) = 5 \n" ); document.write( "(x)(x-8) = e^5 \n" ); document.write( "x^2-8 = e^5 \n" ); document.write( "x^2-8x = e^5 \n" ); document.write( "x^2-8x-e^5 = 0 \n" ); document.write( "Solving using the \"quadratic formula\" yields: \n" ); document.write( "x = {16.82, -8.82} \n" ); document.write( "Since you can't take the ln of a negative number, the -8.82 is an extraneous solution. Throw it out leaving: \n" ); document.write( "x = 16.82 \n" ); document.write( ". \n" ); document.write( "Details of quadratic follows: \n" ); document.write( "
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