document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704594>Question 704594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not understand how you do this problem can you please help. Thank you\r<BR>\n" );
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document.write( "Four times the sum of twice the number and three is twelve. Find the number. \r<BR>\n" );
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document.write( "So far I tried 4n*n2+n= \r<BR>\n" );
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document.write( "Am I right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434208 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be n<BR>\n" );
document.write( "twice the number = 2n<BR>\n" );
document.write( "+3\r<BR>\n" );
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document.write( "2n+3\r<BR>\n" );
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document.write( "four timesthe sum  = 4(2n+3)\r<BR>\n" );
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document.write( "4(2n+3)=12\r<BR>\n" );
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document.write( "8n+12=12<BR>\n" );
document.write( "8n= 12-12<BR>\n" );
document.write( "8n=0<BR>\n" );
document.write( "n=0<BR>\n" );
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