document.write( "Question 704662: sang has invested $48,000, part at 6% and the rest in a higher risk investment at 10%. How much did she invest at each rate to receive $4000 in interest after one year? \n" ); document.write( "
Algebra.Com's Answer #434205 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 10.00% per annum ------------ Amount invested = y
\n" ); document.write( " 48000
\n" ); document.write( "Interest----- 4000
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 10.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 48000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 10.00% y= 4000
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 10 y= 400000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -288000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 112000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 28000
\n" ); document.write( "Part I 6.00% $ 20000
\n" ); document.write( "Part II 10.00% $ 28000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "20000 --------- 6.00% ------- 1200.00
\n" ); document.write( "28000 ------------- 10.00% ------- 2800.00
\n" ); document.write( "Total -------------------- 4000.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
\n" );