document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704645>Question 704645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36 inches, and the area is 77 square inches. Find the length and width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434197 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2(L+W)\r<BR>\n" );
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document.write( "2(L+W) = 36<BR>\n" );
document.write( "L+W= 18\r<BR>\n" );
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document.write( "Area = 77 in^2\r<BR>\n" );
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document.write( "area = L*W\r<BR>\n" );
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document.write( "L*W= 77<BR>\n" );
document.write( "L= 77/W\r<BR>\n" );
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document.write( "substitute L in first equation\r<BR>\n" );
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document.write( "77/W + W = 18\r<BR>\n" );
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document.write( "multiply by W<BR>\n" );
document.write( "77+W^2= 18W\r<BR>\n" );
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document.write( "W^2-18W+77=0<BR>\n" );
document.write( "W^2-11W-7W+77=0<BR>\n" );
document.write( "W(W-11)-7(W-11) =0\r<BR>\n" );
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document.write( "(W-11)(W-7)=0\r<BR>\n" );
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document.write( "therefore the dimensions are 7& 11 m </SPAN>\n" );
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