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document.write( " A jet plane, flying 165 mph faster than a propeller plane, travels 2970 miles in 3 hours less time than the propeller plane takes to fly the same distance. How fast does each plane fly? \n" );
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Algebra.Com's Answer #434117 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "2970=(165+R)(T-3) \n" ); document.write( "2970=RT \n" ); document.write( "T=2970/R \n" ); document.write( "2970=(165+R)(2970/R-3) \n" ); document.write( "2970=165*2970/R-3R+2970R/R-3*165 \n" ); document.write( "2970=490050/R-3R+2970-495 \n" ); document.write( "2970-2970+495=490050/R-3R \n" ); document.write( "495=(490050-3R^2)/R \n" ); document.write( "495R=490050-3R^2 \n" ); document.write( "3R^2+495R-490050=0 \n" ); document.write( "3(R^2+165-163350)=0 \n" ); document.write( "3(R-330)(R+495)=0 \n" ); document.write( "R-330=0 \n" ); document.write( "R=330 RATE OF THE PROPELLER PLANE. \n" ); document.write( "330+165=495 RATE OF THE JET. \n" ); document.write( "2970=330T \n" ); document.write( "2790/330=T \n" ); document.write( "T=9 HOURS FOR THE PROPELLAR PLANE. \n" ); document.write( "PROOF: \n" ); document.write( "2970=495(9-3) \n" ); document.write( "2970=495*6 \n" ); document.write( "2970=2970 \n" ); document.write( " |