document.write( "Question 704504: How do you solve this false proof and what is the mistake in the proof?
\n" ); document.write( "a=1,b=1
\n" ); document.write( "a=b
\n" ); document.write( "a2=ab
\n" ); document.write( "a2+a2=a2+ab
\n" ); document.write( "2a2=a2+ab
\n" ); document.write( "2a2-2ab=a2-ab
\n" ); document.write( "2(a2-ab)= 1(a2-ab)
\n" ); document.write( "2=1
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Algebra.Com's Answer #434116 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You let/force a = b. \r
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\n" ); document.write( "\n" ); document.write( "So because a = b, this means that \r
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\n" ); document.write( "\n" ); document.write( "a^2 - ab\r
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\n" ); document.write( "\n" ); document.write( "b^2 - b*b ... plug in a = b (ie replace all copies of 'a' with 'b')\r
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\n" ); document.write( "\n" ); document.write( "b^2 - b^2\r
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\n" ); document.write( "\n" ); document.write( "0\r
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\n" ); document.write( "\n" ); document.write( "So if a = b, then a^2 - ab is equal to 0. \r
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\n" ); document.write( "\n" ); document.write( "When you jump from 2(a^2-ab)= 1(a^2-ab) to 2 = 1 in the last two lines, you are dividing both sides by a^2-ab. But if a = b, then a^2-ab = 0, which means you're dividing both sides by zero...which is undefined.\r
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\n" ); document.write( "\n" ); document.write( "So the last step is NOT a valid algebraic move because you can't divide by zero.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, you can email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "To find other ways to contact me, you can also visit my website: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Thanks,\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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