document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704500>Question 704500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If solution A contains 30% salt and solution B contains 80% salt,a mixture needs 80 ounces that need to contain 65% salt, how much ounces would A and B both need each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434112 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint:\r<BR>\n" );
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document.write( "Translate the given statements/info into these equations\r<BR>\n" );
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document.write( "x+y = 80<BR>\n" );
document.write( "0.3x+0.8y = 80*0.65\r<BR>\n" );
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document.write( "Solve the first equation for y to get y = 80 -x\r<BR>\n" );
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document.write( "Then plug this into the second equation to get\r<BR>\n" );
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document.write( "0.3x+0.8y = 80*0.65\r<BR>\n" );
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document.write( "0.3x+0.8(80 - x) = 80*0.65\r<BR>\n" );
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document.write( "Solve that for x, then use the solution for x to find the solution for y. \r<BR>\n" );
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document.write( "I'll let you do this. If you want to check the answers with me or if you still need help, see my email below. Thanks.\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Jim\r<BR>\n" );
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