document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62603>Question 62603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5cm more than 3 times the width. If the area of the rectangle is 92cm^2, find the dimensions of the rectangle to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43410 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W+5<BR>\n" );
document.write( "92=W(3W+5)<BR>\n" );
document.write( "92=3W^2+5W<BR>\n" );
document.write( "3W^2+5W-92 USING THE QUADRATIC EQUATION WE GET<BR>\n" );
document.write( "W=(-5+-SQRT[25-4*3*-92])/2*3<BR>\n" );
document.write( "W=(-5+-SQRT(25+1104])/6<BR>\n" );
document.write( "W=(-5+-SQRT1129)/6<BR>\n" );
document.write( "W=(-5+-33.6)/6<BR>\n" );
document.write( "W=(-5+33.6)/6<BR>\n" );
document.write( "W=28.6/6<BR>\n" );
document.write( "W=4.767 SOLUTION<BR>\n" );
document.write( "L=3*4.767+5<BR>\n" );
document.write( "L=19.301 SOLUTION<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "4.767*19.301=92<BR>\n" );
document.write( "92=92\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );