document.write( "Question 704475: A chemist wants to make a 10% solution of fertilizer. How much water and how much of a 30% solution should the chemist mix to get 30L of a 10% solution? \n" ); document.write( "
Algebra.Com's Answer #434094 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Question is typical, typical, typical! Rational expression equals a value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be how much water, y is how much of the 30%. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve one of the equations for x and substitute into the other equation and solve for y. Now use either equation to solve for x value. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You'll see that I did not put any \"x\" into the numerator of the rational equation. Do you understand why? ( x*0=0, the water by itself has no fertilizer ). \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since you know 30 liters is the amount of mixture desired, the rational equation can be written, |