document.write( "Question 704475: A chemist wants to make a 10% solution of fertilizer. How much water and how much of a 30% solution should the chemist mix to get 30L of a 10% solution? \n" ); document.write( "
Algebra.Com's Answer #434094 by josgarithmetic(39617)\"\" \"About 
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Question is typical, typical, typical! Rational expression equals a value.\r
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\n" ); document.write( "\n" ); document.write( "Let x be how much water, y is how much of the 30%.
\n" ); document.write( "\"y%2A0.30%2F%28w%2By%29=0.10\"
\n" ); document.write( "\"x%2By=30\"\r
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\n" ); document.write( "\n" ); document.write( "Solve one of the equations for x and substitute into the other equation and solve for y. Now use either equation to solve for x value. \r
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\n" ); document.write( "\n" ); document.write( "You'll see that I did not put any \"x\" into the numerator of the rational equation. Do you understand why? ( x*0=0, the water by itself has no fertilizer ). \r
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\n" ); document.write( "\n" ); document.write( "Since you know 30 liters is the amount of mixture desired, the rational equation can be written, \"y%2A0.30%2F30=0.10\", and in this case is simpler.
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