document.write( "Question 704404: solve this quadratic equation but don't use the quadratic formula
\n" ); document.write( "4x^2+12x+5=0
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Algebra.Com's Answer #434067 by Stitch(470)\"\" \"About 
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First find the factors of 4 form the \"4X%5E2\"
\n" ); document.write( "The factors of 4 are: 1,2,2,4
\n" ); document.write( "Next Find the factors of 5 (the constant)
\n" ); document.write( "The factors of 5 are: 1,5
\n" ); document.write( "Note that the 5 is positive that means that the factors have to both be positive or both negative.
\n" ); document.write( "Now use the factors of 4 and the factors of 5 to come up with the 12X
\n" ); document.write( "2*5 + 2*1 = 12
\n" ); document.write( "So \"4X%5E2+%2B+12X+%2B+5\" can be rewritten as \"%282X+%2B+5%29%2A%282X+%2B+1%29\"
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\n" ); document.write( "Now we have to solve for each part of the equation.
\n" ); document.write( "The equation equals zero when either of the parentheses equal zero.
\n" ); document.write( "\"2X+%2B+5+=+0\"
\n" ); document.write( "Subtract 5 from both sides
\n" ); document.write( "\"2X+=+-5\"
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "\"highlight%28X+=+-5%2F2%29\"
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\n" ); document.write( "\"2X+%2B+1+=+0\"
\n" ); document.write( "Subtract 1 from both sides
\n" ); document.write( "\"2X+=+-1\"
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( "\"highlight_green%28X+=+-1%2F2%29\"
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