document.write( "Question 704338: Bank loaned $13,000 part of it at 6% per year and the rest at 16%
\n" ); document.write( "per year. If the interest received in one year totaled $1500, how much was loaned at 6% \n" ); document.write( "

Algebra.Com's Answer #434036 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount loaned at 6%
\n" ); document.write( " $\"+13000+-+x+\"$ = amount loaned at 16%
\n" ); document.write( "given:
\n" ); document.write( " $\"+.06x+%2B+.16%2A%28+13000+-+x+%29+=+1500+\"$
\n" ); document.write( " $\"+.06x+%2B+2080+-+.16x+=+1500+\"$
\n" ); document.write( " $\"+-.1x+=+-2080+%2B+1500+\"$
\n" ); document.write( " $\"+-.1x+=+-580+\"$
\n" ); document.write( " $\"+x+=+5800+\"$
\n" ); document.write( " $\"+13000+-+x+=+13000+-+580+\"$
\n" ); document.write( " $\"+13000+-+x+=+7200+\"$
\n" ); document.write( "The amount loaned at 6% was $5,800
\n" ); document.write( "The amount loaned at 16% was $7,200
\n" ); document.write( "check:
\n" ); document.write( " $\"+.06x+%2B+.16%2A%28+13000+-+x+%29+=+1500+\"$
\n" ); document.write( " $\"+.06%2A5800+%2B+.16%2A7200+=+1500+\"$
\n" ); document.write( " $\"+348+%2B+1152+=+1500+\"$
\n" ); document.write( " $\"+1500+=+1500+\"$
\n" ); document.write( "OK \n" ); document.write( "

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