document.write( "Question 704262: An investor invested a total of $1,900 in two mutual funds. One fund earned a 5% profit while the other earned a 3% profit. If the investor's total profit was $71, how much was invested in each mutual fund? \n" ); document.write( "

Algebra.Com's Answer #434022 by mananth(16946) $\"\"$ $\"About$

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Part I 5.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 3.00% per annum ------------ Amount invested = y
\n" ); document.write( " 1900
\n" ); document.write( "Interest----- 71
\n" ); document.write( "
\n" ); document.write( "Part I 5.00% per annum ---x
\n" ); document.write( "Part II 3.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 1900 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "5.00% x + 3.00% y= 71
\n" ); document.write( "Multiply by 100
\n" ); document.write( "5 x + 3 y= 7100.00 --------2
\n" ); document.write( "Multiply (1) by -5
\n" ); document.write( "we get
\n" ); document.write( "-5 x -5 y= -9500.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -2400
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 1200
\n" ); document.write( "Part I 5.00% $ 700
\n" ); document.write( "Part II 3.00% $ 1200
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "700 --------- 5.00% ------- 35.00
\n" ); document.write( "1200 ------------- 3.00% ------- 36.00
\n" ); document.write( "Total -------------------- 71.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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