document.write( "Question 704280: You invested $7000 in two accounts paying 8% and 7% annual interest, respectively. If the total interest earned for the year was $500, how much was invested at each rate?
\n" ); document.write( " Let denote the amount of money invested at 8%. Find an expression in terms of for the amount invested at 7%.
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Algebra.Com's Answer #434019 by mananth(16946)\"\" \"About 
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Part I 8.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y
\n" ); document.write( " 7000
\n" ); document.write( "Interest----- 500
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\n" ); document.write( "Part I 8.00% per annum ---x
\n" ); document.write( "Part II 7.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 7000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "8.00% x + 7.00% y= 500
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 7 y= 50000.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -56000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -1 y= -6000
\n" ); document.write( "divide by -1
\n" ); document.write( " y = 6000
\n" ); document.write( "Part I 8.00% $ 1000
\n" ); document.write( "Part II 7.00% $ 6000 \r
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\n" ); document.write( "CHECK
\n" ); document.write( "1000 --------- 8.00% ------- 80.00
\n" ); document.write( "6000 ------------- 7.00% ------- 420.00
\n" ); document.write( "Total -------------------- 500.00
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\n" ); document.write( "m.ananth@hotmail.ca
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