document.write( "Question 704243: Please help me solve this problem.\r
\n" ); document.write( "\n" ); document.write( "A man built a walk of uniform width around a rectangular pool. If the area of the walk is 203 square feet and the dimensions of the pool are 11 feet by 11 feet, how wide is the walk?
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Algebra.Com's Answer #433984 by DrBeeee(684)\"\" \"About 
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Let w = the width of the walk.
\n" ); document.write( "Then the two dimensions of the walk and pool are both (11 + 2*w).
\n" ); document.write( "The area of the walkway is the total area minus the pool area or
\n" ); document.write( "(1) (11 + 2*w)^2 - 11^2 = 203 or
\n" ); document.write( "(2) 121 + 44*w + 4*w^2 - 121 = 203 or
\n" ); document.write( "(3) 4*w^2 + 44*w - 203 = 0
\n" ); document.write( "Use the quadratic equation to get the positive value of the width as
\n" ); document.write( "(4) w = 3.5
\n" ); document.write( "Check this value in (1)
\n" ); document.write( "Is ((11 + 2*3.5)^2 - 11^2 = 203)?
\n" ); document.write( "Is ((11 + 7)^2 - 121 = 203)?
\n" ); document.write( "Is (18^2 - 121 = 203)?
\n" ); document.write( "Is (324 - 121 = 203)?
\n" ); document.write( "Is (203 = 203)? Yes
\n" ); document.write( "Answer: The width of the walk is 3.5 feet.
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