document.write( "Question 704198: I'm getting stuck at the end of this one...any help would be greatly appreciated!a pen with one side against a wall WITH 6M of fencing. X is the width and the length is (6-2x). The area is a=x(6-2x).
\n" ); document.write( " A). What dimensions of the pen will produce the maximum area?
\n" ); document.write( " B) what is the maximum area?
\n" ); document.write( " I have done the following
\n" ); document.write( " A=(6x-2x)
\n" ); document.write( " Max area occurs at axis of symmetry
\n" ); document.write( "X=-6/-4
\n" ); document.write( " 3/2 is the max area
\n" ); document.write( " L=6-2(3/2)
\n" ); document.write( " Length=5.5?
\n" ); document.write( " I have a hard time working with fractions...any help would be greatly appreciated!
\n" ); document.write( "

Algebra.Com's Answer #433965 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+A+=+x%2A%28+6+-+2x+%29+\"
\n" ); document.write( "\"+A+=+-2x%5E2+%2B+6x+\"
\n" ); document.write( "This is a parabola with a maximum
\n" ); document.write( "The x-coordinate of the vertex is at
\n" ); document.write( "\"+x%5Bv%5D+=+-b%2F%282a%29+\"
\n" ); document.write( "\"+x%5Bv%5D+=+-6%2F%282%2A%28-2%29%29+\"
\n" ); document.write( "\"+x%5Bv%5D+=+3%2F2+\"
\n" ); document.write( "width = 3/2
\n" ); document.write( "length = \"+6+-+2x+=+6+-+2%2A%283%2F2%29+%29+\"
\n" ); document.write( "\"+6+-+2%2A%283%2F2%29+=+3+\"
\n" ); document.write( "-----------------
\n" ); document.write( "So, the 2 sides are 3/2 + 3/2 = 3
\n" ); document.write( "and the length = 3
\n" ); document.write( "Total length = \"+3+%2B+3+=+6+\"
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
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