document.write( "Question 704037: a 50 foot tower is located on the side of the mountain that is inclined 35 degrees to the horizontal. a guy wire is to be attached to the top of the tower and anchored at a point 145 feet downhill from the base of the tower. find the shortest length of wire needed. \n" ); document.write( "
Algebra.Com's Answer #433924 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a 50 foot tower is located on the side of the mountain that is inclined 35 degrees to the horizontal. \n" ); document.write( " a guy wire is to be attached to the top of the tower and anchored at a point 145 feet downhill from the base of the tower. \n" ); document.write( " find the shortest length of wire needed. \n" ); document.write( ": \n" ); document.write( "This is a side-angle-side problem \n" ); document.write( "The angle opposite the guy wire is made with the tower and the slanting ground \n" ); document.write( "35 + 90 = 125 degrees \n" ); document.write( ": \n" ); document.write( "We can use the law of cosines, \n" ); document.write( "c^2 = a^2 + b^2 - 2bc*cos(C) where \n" ); document.write( "a = 145 \n" ); document.write( "b = 50 \n" ); document.write( "c = guy wire length \n" ); document.write( "C = the angle of 125 degrees \n" ); document.write( ": \n" ); document.write( "c^2 = 145^2 + 50^2 - 2(145*50)*cos(125) \n" ); document.write( "c^2 = 21025 + 2500 - 2(7250)*-.573576 \n" ); document.write( "c^2 = 23525 - 14500 * -.573576 \n" ); document.write( "c^2 = 23525 - (-88316.86) \n" ); document.write( "c^2 = 23525 + 88316.86 \n" ); document.write( "c = \n" ); document.write( "c = 178.44 ft is the length of the guy wire \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You should check my math here, to confirm this solution \n" ); document.write( " |