document.write( "Question 704037: a 50 foot tower is located on the side of the mountain that is inclined 35 degrees to the horizontal. a guy wire is to be attached to the top of the tower and anchored at a point 145 feet downhill from the base of the tower. find the shortest length of wire needed. \n" ); document.write( "
Algebra.Com's Answer #433924 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a 50 foot tower is located on the side of the mountain that is inclined 35 degrees to the horizontal.
\n" ); document.write( " a guy wire is to be attached to the top of the tower and anchored at a point 145 feet downhill from the base of the tower.
\n" ); document.write( " find the shortest length of wire needed.
\n" ); document.write( ":
\n" ); document.write( "This is a side-angle-side problem
\n" ); document.write( "The angle opposite the guy wire is made with the tower and the slanting ground
\n" ); document.write( "35 + 90 = 125 degrees
\n" ); document.write( ":
\n" ); document.write( "We can use the law of cosines,
\n" ); document.write( "c^2 = a^2 + b^2 - 2bc*cos(C) where
\n" ); document.write( "a = 145
\n" ); document.write( "b = 50
\n" ); document.write( "c = guy wire length
\n" ); document.write( "C = the angle of 125 degrees
\n" ); document.write( ":
\n" ); document.write( "c^2 = 145^2 + 50^2 - 2(145*50)*cos(125)
\n" ); document.write( "c^2 = 21025 + 2500 - 2(7250)*-.573576
\n" ); document.write( "c^2 = 23525 - 14500 * -.573576
\n" ); document.write( "c^2 = 23525 - (-88316.86)
\n" ); document.write( "c^2 = 23525 + 88316.86
\n" ); document.write( "c = \"sqrt%2831841.86%29\"
\n" ); document.write( "c = 178.44 ft is the length of the guy wire
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "You should check my math here, to confirm this solution
\n" ); document.write( "
\n" );