document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704087>Question 704087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find 3 consecutive integers so that 3 times the first increased by twice the<BR>\n" );
document.write( "second is 2 less than 4 times the third one.<BR>\n" );
document.write( "My idea starts: 3x + 2x = 4x - 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433915 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the 3 consecutive integers are x-1 ,x & x+1<BR>\n" );
document.write( "now 3 times the first increased by twice the  second is 2 less than 4 times the third one<BR>\n" );
document.write( "so 3(x-1)+2x=4(x+1)-2<BR>\n" );
document.write( "or 3x-3+2x=4x+4-2<BR>\n" );
document.write( "or x=5<BR>\n" );
document.write( "so the 3 consecutive integers are 4,5,6<BR>\n" );
document.write( "ans </SPAN>\n" );
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