document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704081>Question 704081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two marathon runners leave the same point at the same time and travel in opposite directions. one runs at a rate that is 0.75 miles per hour faster than the other. after 3 hours they are 44.25 miles apart. how far did each runner travel? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433910 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one runner runs at x miles/hr<BR>\n" );
document.write( "the other runs at (x+0.75) miles/hr<BR>\n" );
document.write( "they   travel in opposite directions<BR>\n" );
document.write( "in one hr the distance between them is x+(x+0.75) miles=2x+0.75<BR>\n" );
document.write( "so in 3 hrs the distance=3(2x+0.75)=6x+2.25<BR>\n" );
document.write( "so 6x+2.25=44.25<BR>\n" );
document.write( "or 6x=44.25-2.25=42<BR>\n" );
document.write( "or x=7 miles/hr=speed of one runner<BR>\n" );
document.write( "speed of other  DISABLED_event_one= 7.75 miles/hr<BR>\n" );
document.write( "the distance traveled in 3 hrs by<BR>\n" );
document.write( "1st runner=7*3=21 iles<BR>\n" );
document.write( "2nd runner=7.75*3 =23.25 miles<BR>\n" );
document.write( "ans </SPAN>\n" );
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