document.write( "Question 703978: A motorboat can maintain a constant speed of 38 miles per hour relative to the water. The boat makes a trip upstream to a certain point in 55 minutes; the return trip take 40 minutes. what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #433908 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "D=(38-C)55/60
\n" ); document.write( "D=(44+C)40/60
\n" ); document.write( "55(38-C/60=40(44+C)/60 CANCEL OUT THE DENOMINATORS.
\n" ); document.write( "55(38-C)=40(44+C)
\n" ); document.write( "2090-55C=1760+40C
\n" ); document.write( "-55C-40C=1760-2090
\n" ); document.write( "-95C=-330
\n" ); document.write( "C=-330/-95
\n" ); document.write( "C=3.47 MPH. FOR THE CURRENT.
\n" ); document.write( "PROOF:
\n" ); document.write( "55(38-3.47)=40(44+3.47)
\n" ); document.write( "55*34.53=40*47.47
\n" ); document.write( "1899=1899\r
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