document.write( "Question 703978: A motorboat can maintain a constant speed of 38 miles per hour relative to the water. The boat makes a trip upstream to a certain point in 55 minutes; the return trip take 40 minutes. what is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #433908 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=(38-C)55/60 \n" ); document.write( "D=(44+C)40/60 \n" ); document.write( "55(38-C/60=40(44+C)/60 CANCEL OUT THE DENOMINATORS. \n" ); document.write( "55(38-C)=40(44+C) \n" ); document.write( "2090-55C=1760+40C \n" ); document.write( "-55C-40C=1760-2090 \n" ); document.write( "-95C=-330 \n" ); document.write( "C=-330/-95 \n" ); document.write( "C=3.47 MPH. FOR THE CURRENT. \n" ); document.write( "PROOF: \n" ); document.write( "55(38-3.47)=40(44+3.47) \n" ); document.write( "55*34.53=40*47.47 \n" ); document.write( "1899=1899\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |