document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704073>Question 704073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the 3 consecutive terms of arithmetic progression is 27.The product of the first 2 terms is 36.What are the first 3 terms of the progression?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433899 by </B><A HREF=/tutors/aboutme.mpl?userid=Anushka><B>Anushka(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Anushka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Anushka><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let first no. =x<BR>\n" );
document.write( "    second no. =x+y<BR>\n" );
document.write( "    third no. =x+2y<BR>\n" );
document.write( "given,<BR>\n" );
document.write( " x+x+y+x+2y=27<BR>\n" );
document.write( " 3x+3y=27<BR>\n" );
document.write( " x+y=9<BR>\n" );
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document.write( "also given,<BR>\n" );
document.write( " x(x+y)=36<BR>\n" );
document.write( "dividing both,\r<BR>\n" );
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document.write( " x(x+y)/x+y = 36/9<BR>\n" );
document.write( " x=4<BR>\n" );
document.write( " y=5\r<BR>\n" );
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document.write( "Ans. First no.=4, Second no.=9, third no.=14 </SPAN>\n" );
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