document.write( "Question 704018: 3 circle, radii of centre PQR are 3.5 cm, x cm, 7 cm. Given that angle of PQR = 90 degree.
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document.write( "a. show that
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document.write( "b. find x
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Algebra.Com's Answer #433895 by sachi(548)![]() ![]() You can put this solution on YOUR website! 3 circle, radii of centre PQR are 3.5 cm, x cm, 7 cm. Given that angle of PQR = 90 degree.& of course the missing part is they are touching each other \n" ); document.write( "so PQ=3.5+x=7/2*x QR=7+x & PR=7+3.5=7+7/2=21/2 \n" ); document.write( "PQR is a right triangle \n" ); document.write( "so PQ^2+QR^2=PR^2 \n" ); document.write( "or(7/2+x)^2+(7+x)^2=(21/2)^2=441/4 \n" ); document.write( "or 49/4+x^2+7x+49+x^2+14x=441/4 \n" ); document.write( "or 2x^2+21x=441/4-49/4-49=49 \n" ); document.write( "or 2x^2+21x-49=0 ANS a \n" ); document.write( " now multiplying 8 on both sides \n" ); document.write( "16x^2+168x-392=0 \n" ); document.write( "or (4x)^2+2*4x*21+441-441-392=0 \n" ); document.write( "or (4x+21)^2=833 \n" ); document.write( "or x=(-21+/-sqrt833)/4 \n" ); document.write( "ans \n" ); document.write( " |