document.write( "Question 704042: 5x + 4y = 22, 3x + 5y =21 using substitution method and 3x + 2y =10, x + 2y =7 using elimination method \n" ); document.write( "
Algebra.Com's Answer #433882 by sachi(548)\"\" \"About 
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using substitution method
\n" ); document.write( "5x + 4y = 22.....A
\n" ); document.write( " 3x + 5y =21 ....B
\n" ); document.write( "from A
\n" ); document.write( "5x = 22- 4y
\n" ); document.write( "or x=(22- 4y)/5....C
\n" ); document.write( "substituting the value of x from C in B
\n" ); document.write( "3(22- 4y)/5 + 5y =21
\n" ); document.write( "or 3(22- 4y) + 25y =105 multiplying both sides by 5
\n" ); document.write( "or 66-12y+25y=105
\n" ); document.write( "or 13y=105-66=39
\n" ); document.write( "or y=39/13=3
\n" ); document.write( "from C
\n" ); document.write( "x=(22-12)/5=2
\n" ); document.write( "so x=2 & y=3\r
\n" ); document.write( "\n" ); document.write( "using elimination method
\n" ); document.write( " 3x + 2y =10......D
\n" ); document.write( " x + 2y =7 .......E
\n" ); document.write( "multiplying both sides of E by 3
\n" ); document.write( " 3x + 6y =21........F
\n" ); document.write( " 3x + 2y =10........D
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\n" ); document.write( " 4y=11
\n" ); document.write( "or y=11/4
\n" ); document.write( "from E
\n" ); document.write( "x+2*11/4=7
\n" ); document.write( "or x=7-11/2=3/2
\n" ); document.write( "so x=3/2& y=11/4
\n" ); document.write( "ans\r
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