document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704032>Question 704032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> linear equation in one variable:<BR>\n" );
document.write( "             An altitude of a triangle is 5/3 of its corresponding base.If the altitude is increased by 4 and then base is decreased by 2 its area remain unchanged.Find alitude and base of its triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433875 by </B><A HREF=/tutors/aboutme.mpl?userid=nshah11><B>nshah11(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nshah11><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b = base and altitude = 5b/3\r<BR>\n" );
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document.write( "Area = 1/2(b)(h) = 1/2(5b/3)(b) = (5b^2)/6\r<BR>\n" );
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document.write( "Altitude increased by 4 = 5b/3 + 4\r<BR>\n" );
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document.write( "Base decreased by 2 = b - 2\r<BR>\n" );
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document.write( "(5b/3 + 4)(b - 2) = (5b^2)/3\r<BR>\n" );
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document.write( "5b^2/3 - 10b/3 + 4b - 8 = (5b^2)/3\r<BR>\n" );
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document.write( "2b/3 = 8\r<BR>\n" );
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document.write( "b = 12, h = 20 </SPAN>\n" );
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