document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704013>Question 704013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plumber wishes to cut a 26 foot length of pipe into two pieces. the longer piece needs to be 7 feet less than twice the length of the shorter piece. where should the plumber cut the pipe? <BR>\n" );
document.write( "thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433857 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A plumber wishes to cut a 26 foot length of pipe into two pieces. the longer piece needs to be 7 feet less than twice the length of the shorter piece. where should the plumber cut the pipe? <BR>\n" );
document.write( "------<BR>\n" );
document.write( "1st piece: x<BR>\n" );
document.write( "2nd: 2x-7<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x + 2x-7 = 26<BR>\n" );
document.write( "3x = 33<BR>\n" );
document.write( "x = 11 ft (1st piece)<BR>\n" );
document.write( "2x-7 = 22-7 = 15 ft (2nd piece)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );