document.write( "Question 704008: The width of a rectangle is 2 inches less than its length. Find the length and width if the area of the rectangle is 35 inches wide. \n" ); document.write( "
Algebra.Com's Answer #433852 by algebrahouse.com(1659)\"\" \"About 
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x = length
\n" ); document.write( "x - 2 = width {width is 2 less than length}\r
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\n" ); document.write( "\n" ); document.write( "Area = length x width\r
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\n" ); document.write( "\n" ); document.write( "x(x - 2) = 35 {area is length x width}
\n" ); document.write( "x² - 2x = 35 {used distributive property}
\n" ); document.write( "x² - 2x - 35 = 0 {subtracted 35 from each side}
\n" ); document.write( "(x - 7)(x + 5) = 0 {factored into two binomials}
\n" ); document.write( "x - 7 = 0 or x + 5 = 0 {set each factor equal to 0}
\n" ); document.write( "x = 7 or x = -5 {solved each equation for x}
\n" ); document.write( "x = 7 {length cannot be negative
\n" ); document.write( "x - 2 = 5 {substituted 7, in for x, into x - 2}\r
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\n" ); document.write( "\n" ); document.write( "length is 7 in. and width is 5 in.
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