document.write( "Question 703964: The length of a rectangle is a = 3 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 80 cm.\r
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\n" ); document.write( "\n" ); document.write( "This is what I have:\r
\n" ); document.write( "\n" ); document.write( " 80=6w-6
\n" ); document.write( " +6 +6\r
\n" ); document.write( "\n" ); document.write( " 86=6w
\n" ); document.write( " ------
\n" ); document.write( " 6 6\r
\n" ); document.write( "\n" ); document.write( " 14.3333333=w
\n" ); document.write( " 14.33=w
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Algebra.Com's Answer #433827 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Always check your answer. If the width is 14.33 then the lenght is 28.66 - 3 or 25.66, then the perimeter is 2*(14.33+25.66) or 80. So your answer is correct.
\n" ); document.write( "Let w = the width and
\n" ); document.write( "Let a = length
\n" ); document.write( "Then, from the problem statement we have
\n" ); document.write( "(1) a = 2*w - 3
\n" ); document.write( "The perimeter, p, is the sum of the 4 side or
\n" ); document.write( "(2) p = 2*a + 2*w or
\n" ); document.write( "(3) p = 2*(2*w - 3) + 2*w or
\n" ); document.write( "(4) p = 4*w - 6 + 2*w or
\n" ); document.write( "(5) p = 6*w - 6
\n" ); document.write( "Using the maximum value of p as 80 we have
\n" ); document.write( "(6) 6*w - 6 <= 80 or
\n" ); document.write( "(7) w <= 86/6 or
\n" ); document.write( "(8) w <= 14.33...
\n" ); document.write( "Answer: The largest integer value of the width is 14 cm.
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