document.write( "Question 703880: a rectangle is three times as long as it is wide. the rectangle has its length increased in the ratio of 3:1 and its width decreases in the ratio 1:2.
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document.write( "a. in what ratio is its area changed?
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document.write( "b. in what ratio is its perimeter changed? \n" );
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Algebra.Com's Answer #433818 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! a rectangle is three times as long as it is wide. \n" ); document.write( "L = 3W \n" ); document.write( " the rectangle has its length increased in the ratio of 3:1 and its width decreases in the ratio 1:2. \n" ); document.write( "3L by .5W \n" ); document.write( ": \n" ); document.write( "a. in what ratio is its area changed? \n" ); document.write( "Old area:new area \n" ); document.write( "LW:3L*.5W \n" ); document.write( "LW:1.5LW \n" ); document.write( "get rid of the decimal mult both by 2 \n" ); document.write( "2LW:3LW \n" ); document.write( "divide both by LW \n" ); document.write( "2:3 is the ratio of old area to new area \n" ); document.write( ": \n" ); document.write( "b. in what ratio is its perimeter changed? \n" ); document.write( "(2L+2W):(2*3L+.5*2W) \n" ); document.write( "2(L+W):(6L+1W) \n" ); document.write( "Replace L with 3W \n" ); document.write( "2(3W+W):(18W+W) \n" ); document.write( "2(4W):19W \n" ); document.write( "8W:19W \n" ); document.write( "8:19 is the old perimeter to the new perimeter \n" ); document.write( " |