document.write( "Question 703880: a rectangle is three times as long as it is wide. the rectangle has its length increased in the ratio of 3:1 and its width decreases in the ratio 1:2.
\n" ); document.write( "a. in what ratio is its area changed?
\n" ); document.write( "b. in what ratio is its perimeter changed?
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Algebra.Com's Answer #433818 by ankor@dixie-net.com(22740)\"\" \"About 
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a rectangle is three times as long as it is wide.
\n" ); document.write( "L = 3W
\n" ); document.write( " the rectangle has its length increased in the ratio of 3:1 and its width decreases in the ratio 1:2.
\n" ); document.write( "3L by .5W
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\n" ); document.write( "a. in what ratio is its area changed?
\n" ); document.write( "Old area:new area
\n" ); document.write( "LW:3L*.5W
\n" ); document.write( "LW:1.5LW
\n" ); document.write( "get rid of the decimal mult both by 2
\n" ); document.write( "2LW:3LW
\n" ); document.write( "divide both by LW
\n" ); document.write( "2:3 is the ratio of old area to new area
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\n" ); document.write( "b. in what ratio is its perimeter changed?
\n" ); document.write( "(2L+2W):(2*3L+.5*2W)
\n" ); document.write( "2(L+W):(6L+1W)
\n" ); document.write( "Replace L with 3W
\n" ); document.write( "2(3W+W):(18W+W)
\n" ); document.write( "2(4W):19W
\n" ); document.write( "8W:19W
\n" ); document.write( "8:19 is the old perimeter to the new perimeter
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