document.write( "Question 703932: Sorry to bother you, but I'm a bit stuck with this proof.
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Algebra.Com's Answer #433793 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"%282tan%28A%29%29%2F%281%2Btan%5E2%28A%29%29\" = sin(2A)\r\n" );
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document.write( "Work with the left side. Use the identity \"tan%28theta%29=sin%28theta%29%2Fcos%28theta%29\"\r\n" );
document.write( "on the top and use the identity \"1%2Btan%5E2%28theta%29=sec%5E2%28theta%29\"\r\n" );
document.write( "on the bottom:\r\n" );
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document.write( "\"%28++2sin%28A%29%2Fcos%28A%29++%29%2F%28sec%5E2%28A%29%29\" = \r\n" );
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document.write( "Use the identity \"sec%28theta%29=1%2Fcos%28theta%29\" on the bottom:\r\n" );
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document.write( "\"%28++2sin%28A%29%2Fcos%28A%29++%29%2F%28%0D%0A%0D%0A%281%2Fcos%28A%29%29%5E2%0D%0A%0D%0A%29\"\r\n" );
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document.write( "\"%28++2sin%28A%29%2Fcos%28A%29++%29%2F%28%0D%0A%0D%0A1%2Fcos%5E2%28A%29%0D%0A%0D%0A%29\"\r\n" );
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document.write( "Invert and multiply:\r\n" );
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document.write( "\"%28++2sin%28A%29%2Fcos%28A%29++%29%2A%28%0D%0A%0D%0Acos%5E2%28A%29%2F1%0D%0A%0D%0A%29\"\r\n" );
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document.write( "Cancel the cosine in the bottom into one of the cosine\r\n" );
document.write( "factors in the top\r\n" );
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document.write( "2sin(A)cos(A)\r\n" );
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document.write( "We use the identity \"sin%282theta%29=2sin%28theta%29cos%28theta%29\"\r\n" );
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document.write( "sin(2A)\r\n" );
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document.write( "Edwin
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