document.write( "Question 703897: The differance between simple interset and compound interest of a sum oof money $48 at 20% p.a for 2 years . Find the principal..
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document.write( "(Hint assume principal as100) \n" );
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Algebra.Com's Answer #433783 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Following the hint, \n" ); document.write( "if you calculate the interest earned on $100 both ways: \n" ); document.write( "simple 20% p.a. interest for 2 years, \n" ); document.write( "and 20% p.a. compounded annually for 2 years, \n" ); document.write( "you find that compounded interest gives you $4 more. \n" ); document.write( "To get $48 extra from such compounding, you would need to invest 12 times more, or $1200.\r \n" ); document.write( "\n" ); document.write( "To calculate on year's worth of interest at 20% p.a., we multiply the principal \n" ); document.write( "(the beginning balance) times \n" ); document.write( "$ \n" ); document.write( " \n" ); document.write( "At 20% simple interest for 2 years, the second year interest would be calculated as another $ \n" ); document.write( "The total interest for the 2-year period would be $ \n" ); document.write( " \n" ); document.write( "If the interest was compounded annually, \n" ); document.write( "the balance at the end of the first year, \n" ); document.write( "$ \n" ); document.write( "would be the new principal, used to calculate the interest on the second year.The interest for the second year would be \n" ); document.write( "$ \n" ); document.write( "That is an extra $ \n" ); document.write( "The $ \n" ); document.write( "already earned the first year. \n" ); document.write( "The $ \n" ); document.write( "That's called compounding the interest. \n" ); document.write( " \n" ); document.write( "NOTE: \n" ); document.write( "Interest can also be compounded monthly, daily, or continuously. \n" ); document.write( " |