document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703838>Question 703838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> admission to the circus costs $8 for adults and $6 for children. a total of 900 tickets were sold and total sales are $6160. If A represents adults and C represents children create two equations which model the situation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433771 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if one adults ticket costs $8, then 2 would cost $(8X2), 3 would cost $(8X3) etc because there A adults then the cost of their tickets is $(8A).<BR>\n" );
document.write( "In a similar way the children's tickets would cost $(6C).<BR>\n" );
document.write( "the total of these ticket sales comes to $6160 so we can say<BR>\n" );
document.write( "8A+6C=6160<BR>\n" );
document.write( "we also know that 900 tickets were sold to adults and children, so the second equation is<BR>\n" );
document.write( "A+C=900 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );