document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=701606>Question 701606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of salt must be added to 40 grams of a 28% salt solution to obtain a 40% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433699 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (salt)/(salt solution)=0.40\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The salt material is 100% salt.  The current solution is the lower concentration material at 28% or 0.28.  You have 40 grams of this solution and you do not need to know how much resulting solution quantity.\r<BR>\n" );
document.write( "\n" );
document.write( "m= grams of salt solid to add,\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28m%2A1.00%2B40%2A0.28%29%2F%28m%2B40%29=0.40 ALIGN=MIDDLE  ALT=\"%28m%2A1.00%2B40%2A0.28%29%2F%28m%2B40%29=0.40\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Solve for m. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );