document.write( "Question 703791: A conic section has the equation x^2-6x-y^2+4y-4=0. Which one of the following is true?
\n" ); document.write( "1) the equation is a parabola with its vertex at (3,2).
\n" ); document.write( "2) the equation is a circle with its center at (3,2)
\n" ); document.write( "3) the equation is a hyperbola with one vertex at (0,2)
\n" ); document.write( "4) the radius is 2
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Algebra.Com's Answer #433693 by stanbon(75887)\"\" \"About 
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A conic section has the equation x^2-6x-y^2+4y-4=0. Which one of the following is true?
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\n" ); document.write( "Complete the square on the x-terms and on the y-terms:
\n" ); document.write( "x^2-6x+? - (y^2-4y + ?) = -4
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\n" ); document.write( "x^2 -6x + 9 - (y^2-4y+4) = -4+9-4
\n" ); document.write( "Factor:
\n" ); document.write( "(x-3)^2 - (y-2)^2 = 1
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\n" ); document.write( "Ans: The equation is a hyperbola with center at (3,2)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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