document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703781>Question 703781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 15% antifreeze to get a mixture that is 50% antifreeze? use the six step method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433691 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the \"Six Step Method\"?\r<BR>\n" );
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document.write( "Goal is  (MainIngredient)/(TotalMixture)=0.50\r<BR>\n" );
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document.write( "You do not know how much total mixture will result but you know you start with 90 gallons and that its percentage concentration is 15%, or 0.15 as fraction.  You have available a higher concentration material of 60%, or 0.60 as a fraction.\r<BR>\n" );
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document.write( "Where the only variable, v, is the gallons of the 60% antifreeze to add. </SPAN>\n" );
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