document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703761>Question 703761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second of three numbers is 1 less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433681 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second of three numbers is 1 less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers.<BR>\n" );
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document.write( "let x=1st number<BR>\n" );
document.write( "x-1=2nd number<BR>\n" );
document.write( "2x-5=3rd number<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2x-5-x=17<BR>\n" );
document.write( "x=17<BR>\n" );
document.write( "x-1=16<BR>\n" );
document.write( "2x-5=27<BR>\n" );
document.write( "1st number=17<BR>\n" );
document.write( "2nd number=16<BR>\n" );
document.write( "3rd number=27 </SPAN>\n" );
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