document.write( "Question 703712: A rectangle is 4 times as long as it is wide. The area is 196 square feet. What is the perimeter of the rectangle?
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Algebra.Com's Answer #433664 by Simnepi(216) $\"\"$ $\"About$

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let x be the width of the rectangle. The length is four times the width so the length is 4x.
\n" ); document.write( "Now, Area = length multiplied by width so
\n" ); document.write( "196 = 4x * x this is $\"196=4x%5E2\"$
\n" ); document.write( "dividing by 4 gives
\n" ); document.write( " $\"x%5E2=49\"$
\n" ); document.write( "to 'undo' the 'squared' we have to find the square root
\n" ); document.write( " so x= $\"sqrt%2849%29\"$
\n" ); document.write( "therefore x = 7
\n" ); document.write( "Now we find the perimeter of the rectangle
\n" ); document.write( "If x = 7 (the width) then 4x = 28 (the length)
\n" ); document.write( "Perimeter of a rectangle is
\n" ); document.write( "2(length+width) giving
\n" ); document.write( "2(28+7) = 2(35) = 70
\n" ); document.write( "The perimeter is 70 feet \n" ); document.write( "

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