document.write( "Question 703560: how do i work out this equation 4√3:(b)+5=√3:(b)-1 i got as far as converting the cube root to 4(b^1/3)+5=(b^1/3)-1 then i got stuck i tired it on jmy calcullator and got b=8 not sure how thou \n" ); document.write( "

Algebra.Com's Answer #433654 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
4√3:(b)+5=√3:(b)-1
\n" ); document.write( ":
\n" ); document.write( "I'm going to write it like this, the cube roots are like terms so we can combine
\n" ); document.write( " $\"4%2A3sqrt%28b%29%2B5+=+3sqrt%28b%29-1\"$
\n" ); document.write( " $\"4%2A3sqrt%28b%29-+3sqrt%28b%29=+-1+-+5\"$
\n" ); document.write( " $\"3%2A3sqrt%28b%29+=+-6\"$
\n" ); document.write( "divide both sides by 3
\n" ); document.write( " $\"3sqrt%28b%29+=+-2\"$
\n" ); document.write( "Cube both sides
\n" ); document.write( "b = -8
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\n" ); document.write( ":
\n" ); document.write( "See if that checks out on a calc; enter
\n" ); document.write( "4(-8^(1/3)) + 5 = -3
\n" ); document.write( "and
\n" ); document.write( "-8^(1/3) - 1 = -3; equality reigns, so a good solution
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