document.write( "Question 703656: Write the point-slope form of the equation passing through (5, -1) with a slope of 6.
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Algebra.Com's Answer #433637 by Nfrey78(18)\"\" \"About 
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Write the point-slope form of the equation passing through (5, -1) with a slope of 6.\r
\n" ); document.write( "\n" ); document.write( "y = mx + b is the slope-intercept form for a linear equation where m stands for slope and b stands for y-intercept\r
\n" ); document.write( "\n" ); document.write( "here you are given a point (5, -1) and m = 6
\n" ); document.write( "The coordinates of the point give you an x and y value. x = 5 and y = -1
\n" ); document.write( "plug these into y = mx + b to find b
\n" ); document.write( "-1 = (6)(5) + b
\n" ); document.write( "- 1 = 30 + b
\n" ); document.write( "subtract 30 from both sides
\n" ); document.write( "-31 = b
\n" ); document.write( "now put the m and b that we just found back into y = mx + b
\n" ); document.write( "y = 6x - 31\r
\n" ); document.write( "\n" ); document.write( "We can check by graphing
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+6%2C+-35%2C+5%2C+6x+-+31%29\"\r
\n" ); document.write( "\n" ); document.write( "We can see that (5, -1) is a point on this graph
\n" ); document.write( "Again the solution is \"y+=+6x+-+31\"
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