document.write( "Question 703695: what is the solution of the equation?
\n" ); document.write( "sqrt(2x+13) -5 = x
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Algebra.Com's Answer #433631 by Nfrey78(18)\"\" \"About 
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what is the solution of the equation?
\n" ); document.write( "\"sqrt%282x%2B13%29+-5+=+x\"
\n" ); document.write( "To solve a radical equation we first need to get the radical, i.e. square root, by itself
\n" ); document.write( "Add 5 to both sides to get
\n" ); document.write( "\"sqrt%282x%2B13%29=+x+%2B+5\"
\n" ); document.write( "To \"undo\" the square root function, we need to do the inverse, which is square both sides. Notice that the square root is now undone
\n" ); document.write( "\"2x%2B13=+%28x+%2B+5%29%5E2\"
\n" ); document.write( "Squaring the right side is the same as (x + 5)(x + 5). Many students often make the mistake of saying it would be \"x%5E2+%2B+25\" forgetting that they need to FOIL this expression out. Done correctly we should get
\n" ); document.write( "\"2x%2B13=+x%5E2+%2B+10x+%2B+25\"
\n" ); document.write( "We can see this results in a quadratic, which means we have to set it to zero, moving everything to one side
\n" ); document.write( "\"0=+x%5E2+%2B+10x+-2x+%2B+25+-+13\"
\n" ); document.write( "Simplifying the right side by combining like terms yields
\n" ); document.write( "\"0=+x%5E2+%2B+8x+%2B+12\"
\n" ); document.write( "After set to zero we factor. What multiplies to give 12 but adds to 8?
\n" ); document.write( "\"0=+%28x+%2B+6%29%28x+%2B+2%29\"
\n" ); document.write( "Set each factor to zero
\n" ); document.write( "\"+x%2B6+=+0\" or \"x+%2B+2=0\"
\n" ); document.write( "and solve for x to get our solutions!
\n" ); document.write( "\"x+=+-6\" or \"x+=+-2\"
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