document.write( "Question 703652: Two trains heading towards each other are 400 miles apart one train travels 15 miles per hour faster than the other train if they arrive at the same station in 5 hours how fast is each train traveling \n" ); document.write( "
Algebra.Com's Answer #433614 by Stitch(470)\"\" \"About 
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Let A = Speed of Train #1
\n" ); document.write( "Let B = Speed of Train #2
\n" ); document.write( "Equation 1: \"A+=+B+%2B+15\" (One train is 15mph faster than the other)
\n" ); document.write( "Eqauation 2: \"5A+=+400+-+5B\"
\n" ); document.write( "--------------------------------
\n" ); document.write( "Since we know the value of A, substitute (B+15) into equation 2 for A
\n" ); document.write( "Eqauation 2: \"5A+=+400+-+5B\"
\n" ); document.write( "\"5%2A%28B+%2B+15%29+=+400+-+5B\"
\n" ); document.write( "Multiply the 5 through.
\n" ); document.write( "\"5B+%2B+75+=+400+-+5B\"
\n" ); document.write( "Add 5B to both sides
\n" ); document.write( "\"10B+%2B+75+=+400\"
\n" ); document.write( "Subtract 75 from both sides
\n" ); document.write( "\"10B+=+325\"
\n" ); document.write( "Divide both sides by 10
\n" ); document.write( "\"highlight%28B+=+32.5mph%29\"
\n" ); document.write( "Now plug 32.5 into equation 1 for B
\n" ); document.write( "Equation 1: \"A+=+B+%2B+15\"
\n" ); document.write( "\"A+=+%2832.5%29+%2B+15\"
\n" ); document.write( "\"highlight%28A+=+47.5mph%29\"
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