document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703523>Question 703523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant combines coffee costing $6.00 per pound with coffee costing $4.50 per pound. How many pounds of each should be used to make 30 lb of a blend costing $5.20 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433573 by </B><A HREF=/tutors/aboutme.mpl?userid=nshah11><B>nshah11(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nshah11><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume x lbs of $6/lb is coffee is mixed while (30 - x) lbs of $4.5/lb coffee is mixed.\r<BR>\n" );
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document.write( "(6x + 4.5(30 - x))/30 = 5.2\r<BR>\n" );
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document.write( "1.5x + 135 = 156\r<BR>\n" );
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document.write( "x = 21(2/3) = 14 lbs\r<BR>\n" );
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document.write( "30 - x = 16 lbs </SPAN>\n" );
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