document.write( "Question 62581This question is from textbook beginning algebra
\n" ); document.write( ": 37. x/4-y/3=4
\n" ); document.write( " x/4-y/4=-1
\n" ); document.write( "39. 2/5x-1/6y=7/10
\n" ); document.write( " 3/4x-2/3y=19/8\r
\n" ); document.write( "\n" ); document.write( "I tried solving these equations I know the lcd the first equation is 30 and 24 the lcm is 3,2 the book has the correct ans for 39 is (1/2,-3).\r
\n" ); document.write( "\n" ); document.write( "37 equation is alittle confusing or maybe I am making to difficult. please help me. \n" ); document.write( "
Algebra.Com's Answer #43357 by stanbon(75887)\"\" \"About 
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1st: x/4-y/3= 4
\n" ); document.write( "2nd: x/4-y/4=-1
\n" ); document.write( "----------
\n" ); document.write( "Subtract 2nd from 1st to get:
\n" ); document.write( "3rd: -y/3+y/4=5
\n" ); document.write( "Multiply 3rd by 12 to get:
\n" ); document.write( "-4y+3y=60
\n" ); document.write( "-y=60
\n" ); document.write( "y=-60
\n" ); document.write( "-----------
\n" ); document.write( "Substitute into 1st to solve for y, as follows:
\n" ); document.write( "(x/4)+20=4
\n" ); document.write( "x/4 =-16
\n" ); document.write( "x=-64
\n" ); document.write( "--------
\n" ); document.write( "Final solution:
\n" ); document.write( "x=-64, y=-60\r
\n" ); document.write( "\n" ); document.write( "- \n" ); document.write( "
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