document.write( "Question 703564: Log base 2 (8x) - log base 2 (x squared minus 1) = log base 2 3 \n" ); document.write( "
Algebra.Com's Answer #433552 by nerdybill(7384)\"\" \"About 
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Log base 2 (8x) - log base 2 (x squared minus 1) = log base 2 3
\n" ); document.write( "\"log%282%2C8x%29+-+log%282%2Cx%5E2-1%29+=+log%282%2C3%29\"
\n" ); document.write( "\"log%282%2C8x%2F%28x%5E2-1%29%29+=+log%282%2C3%29\"
\n" ); document.write( "\"8x%2F%28x%5E2-1%29+=+3\"
\n" ); document.write( "\"8x+=+3%28x%5E2-1%29\"
\n" ); document.write( "\"8x+=+3x%5E2-3%29\"
\n" ); document.write( "\"0+=+3x%5E2-8x-3\"
\n" ); document.write( "\"0+=+%283x%2B1%29%28x-3%29\"
\n" ); document.write( "x = {-1/3, 3}
\n" ); document.write( "we can throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 3
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