document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703384>Question 703384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the cooling system of car has a capacity of 15 liters. If the system is currently filled with a mixture that is 40% anitfreeze, how much if this mixture should be drained and replaced with pure anitfreeze so that the system is filled with a solution this is 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433488 by </B><A HREF=/tutors/aboutme.mpl?userid=nshah11><B>nshah11(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nshah11><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume x liters of the mixture should be drained. The x liters consists of 0.40(x) antifreeze.\r<BR>\n" );
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document.write( "Remaining antifreeze after x liters are drained = 15(0.4) - 0.4(x)\r<BR>\n" );
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document.write( "Assume x liters of pure antifreeze is added. If so, then total antifreeze = 6 - 0.4(x) + x = 6 + 0.6(x)\r<BR>\n" );
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document.write( "(6 + 0.6(x))/(15) = 1/2\r<BR>\n" );
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document.write( "12 + 1.2x = 15\r<BR>\n" );
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document.write( "x = 2.5 liters </SPAN>\n" );
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