document.write( "Question 703364: \r
\n" ); document.write( "\n" ); document.write( "A $6000 investment at an annual simple interest rate of 3.3% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
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Algebra.Com's Answer #433473 by checkley79(3341)\"\" \"About 
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6000*.033=.055X
\n" ); document.write( "198=.055X
\n" ); document.write( "X=198/.055
\n" ); document.write( "X=$3600 AMOUNT INVESTED @ 5.5%.\r
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