document.write( "Question 703364: \r
\n" );
document.write( "\n" );
document.write( "A $6000 investment at an annual simple interest rate of 3.3% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #433473 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 6000*.033=.055X \n" ); document.write( "198=.055X \n" ); document.write( "X=198/.055 \n" ); document.write( "X=$3600 AMOUNT INVESTED @ 5.5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |