document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703368>Question 703368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You leave your house at 8 am travelling at an average speed of 50 miles per hour. Your brother leaves the same house at 9am an average speed of 60 miles per hour. How far apart will you be from your brother at noon. \r<BR>\n" );
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document.write( "I know it is d=rt but I'm having difficulty plugging in the numbers. I know you add 50+60 to make 110 since they are going opposite directions, but from there I am stuck.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433467 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You leave your house at 8 am traveling at an average speed of 50 miles per hour. Your brother leaves the same house at 9am an average speed of 60 miles per hour. How far apart will you be from your brother at noon.<BR>\n" );
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document.write( "Your DATA:<BR>\n" );
document.write( "rate = 50 mph ; time = 4 hrs ; distance = 4*50 =  200 miles<BR>\n" );
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document.write( "Brother's DATA:<BR>\n" );
document.write( "rate = 60 mph ; time = 3 hrs ; distance = 3*60 = 180 miles<BR>\n" );
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document.write( "Assuming they go in opposite directions they will be 200+180 = 380 miles apart<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H<BR>\n" );
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