document.write( "Question 62579: I tried this but i think it's wrong can u please help again:\r
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document.write( "Sqrt x+9 +3=x\r
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document.write( "x+9 is in the radical(square root) \n" );
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Algebra.Com's Answer #43346 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Sqrt(x+9) +3=x \n" ); document.write( "sqrt(x+9) = x-3 \n" ); document.write( "Square both sides to get: \n" ); document.write( "x+9 = x^2-6x+9 \n" ); document.write( "x^2-7x=0 \n" ); document.write( "x(x-7)=0 \n" ); document.write( "x=0 or x=7 \n" ); document.write( "Check answer in the orignal equation: \n" ); document.write( "If x=0, sqrt(0+9)=0-3 \n" ); document.write( "Wrong as sqrt9 = +3 \n" ); document.write( "--------- \n" ); document.write( "If x=7, sqrt(7+9)=7-3 \n" ); document.write( "sqrt16=4 \n" ); document.write( "4=4 \n" ); document.write( "Good solution \n" ); document.write( "----------- \n" ); document.write( "Final solution: \n" ); document.write( "x=7 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |