document.write( "Question 703275: Thank you in advance for an answer to this question. The example 6x^2-9x=60 was given. \r
\n" );
document.write( "\n" );
document.write( "Of course, I set the example to zero, found the greatest fact and this is my result: 3(2x^2-3x-20)=0 was the result which I then factored further by grouping and the result was: 3(2x+5)(x-4)=0 then I set each factor to zero and got the correct answer of x=-5/2 and x=4 which the example showed as the possible results, however, it is confusing to me why we disregard the 3 which is another factor. Can you give me some thoughts regarding this. \r
\n" );
document.write( "\n" );
document.write( "Tina \n" );
document.write( "
Algebra.Com's Answer #433405 by Nfrey78(18)![]() ![]() ![]() You can put this solution on YOUR website! Of course, I set the example to zero, found the greatest fact and this is my result: 3(2x^2-3x-20)=0 was the result which I then factored further by grouping and the result was: 3(2x+5)(x-4)=0 then I set each factor to zero and got the correct answer of x=-5/2 and x=4 which the example showed as the possible results, however, it is confusing to me why we disregard the 3 which is another factor. Can you give me some thoughts regarding this. \r \n" ); document.write( "\n" ); document.write( "Good question! \n" ); document.write( "So if we have two (or more) numbers multiplied together that equal 0, then one or more of those factors must equal zero right? \n" ); document.write( "Well what if we had 3x = 0. 3 time a number equals zero. Then the only solution is x = 0. The 3 doesn't give us any solutions because 3 never equals zero. \n" ); document.write( "You factored correctly: 3(2x + 5)(x - 4) = 0 \n" ); document.write( "You have three numbers that multiply to give zero, \n" ); document.write( "Then we set each factor to zero \n" ); document.write( "3 = 0, 2x + 5 = 0, or x - 4 = 0 \n" ); document.write( "The first equation doesn't give us any solutions, because it is a contradiction, 3 never equals 0. \n" ); document.write( "The only options are that either the second number (2x + 5) or the third number (x - 4) equals 0 (or both). \n" ); document.write( " |