document.write( "Question 703232: \r
\n" ); document.write( "\n" ); document.write( "how many gallons of an 80% alcohol solution must be mixed with 30 gallons of 24% solution to obtain a solution that is 70% alcohol.
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Algebra.Com's Answer #433390 by checkley79(3341)\"\" \"About 
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.80X+.24*30=.70(30+X)
\n" ); document.write( ".80X+7.2=21+.70X
\n" ); document.write( ".80X-.70X=21-7.2
\n" ); document.write( ".10X=13.8
\n" ); document.write( "X=13.8/.10
\n" ); document.write( "X=138 GAL OF 80% SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".80*138+.24*30=.70(30+138)
\n" ); document.write( "110.4+7.2=.70*168
\n" ); document.write( "117.6=117.6
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