document.write( "Question 62571This question is from textbook beginning algebra
\n" ); document.write( ": 33. .2x=.3y-2
\n" ); document.write( " 1.5y=x+.8\r
\n" ); document.write( "\n" ); document.write( "35. 0.5x+2y=1.15
\n" ); document.write( " -3x+0.4y=-0.7\r
\n" ); document.write( "\n" ); document.write( "I was having some problems with these two equation I know that I have to use 10 and multiply by the decimal number but the ans is off or incorrect. Please help me with this step by step. Thanks!!!
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Algebra.Com's Answer #43339 by funmath(2933)\"\" \"About 
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33.
\n" ); document.write( "E1: .2x=.3y-2
\n" ); document.write( "E2: 1.5y=x+.8
\n" ); document.write( "Multiply both E1 and E2 by 10
\n" ); document.write( "E1: 10(.2x)=10(.3y-2) ---> 2x=3y-20
\n" ); document.write( "E2: 10(1.5y)=10(x+.8) ---> 15y=10x+8
\n" ); document.write( "Divide both sides of E1 by 2.
\n" ); document.write( "E1: 2x/2=3y/2-20/2 ---> x=(3/2)y-10
\n" ); document.write( "Substitute x=(3/2)y-10 in for x in E2 and solve for y.
\n" ); document.write( "E2: \"15y=10%28%283%2F2%29y-10%29%2B8\"
\n" ); document.write( "\"15y=5%283y%29-100%2B8\"
\n" ); document.write( "\"15y=15y-92\"
\n" ); document.write( "\"15y-15y=15y-15y-92\"
\n" ); document.write( "\"0=-92\"
\n" ); document.write( "The variable was eliminated and 0 does not = -92, therefore there is no solution. Graphically, these lines are parallel and will never intersect.
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\n" ); document.write( "\n" ); document.write( "35.
\n" ); document.write( "E1: 0.5x+2y=1.15
\n" ); document.write( "E2: -3x+0.4y=-0.7
\n" ); document.write( "Multiply E1 by 100 and E2 by 10.
\n" ); document.write( "E1: 100(0.5x+2y)=100(1.15) ---> 50x+200y=115
\n" ); document.write( "E2: 10(-3x+0.4y)=10(-0.7) ---> -30x+4y=-7
\n" ); document.write( "Multiply E2 by -50 and add E1+E2 and the y's are eliminated.
\n" ); document.write( "E2: -50(-30x+4y)=-50(-7) --> 1500x-200y=350
\n" ); document.write( ":
\n" ); document.write( "50x+200y=115
\n" ); document.write( "1500x-200y=350
\n" ); document.write( "_______________
\n" ); document.write( "1550x=465
\n" ); document.write( "1550x/1550=465/1550
\n" ); document.write( "x=.3
\n" ); document.write( "Let x=.3 in the original E1 and solve for y
\n" ); document.write( "0.5(.3)+2y=1.15
\n" ); document.write( "0.15+2y=1.15
\n" ); document.write( "0.15-0.15+2y=1.15-0.15
\n" ); document.write( "2y=1
\n" ); document.write( "2y/2=1/2
\n" ); document.write( "y=.5
\n" ); document.write( "The solution is (.3,.5)
\n" ); document.write( "Happy Calculating!!!
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