document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=703188>Question 703188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been working on this problem for hours now.  I know what the answer is but whenever i do the problem it does not come out to be right!  Here is the problem:\r<BR>\n" );
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document.write( "The radius of the surface of a circle pool is (2+sqrt(xy^5))meter. Express the area of the pool in simplest form. \r<BR>\n" );
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document.write( "The answer is supposed to be:<BR>\n" );
document.write( "Pi (4+xy^5 +4y^2 sqrt(xy)) m^2\r<BR>\n" );
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document.write( "I just dont understand the steps to take to get there </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #433339 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=433339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You say the radius is \"(2+sqrt(xy^5))meter\". That is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2Bsqrt%28xy%5E5%29%29meter ALIGN=MIDDLE  ALT=\"%282%2Bsqrt%28xy%5E5%29%29meter\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=area+=+pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"area+=+pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=area=pi%2A%282%2Bsqrt%28xy%5E5%29%29%5E2 ALIGN=MIDDLE  ALT=\"area=pi%2A%282%2Bsqrt%28xy%5E5%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%282%5E2%2B4%2Asqrt%28xy%5E5%29%2Bx%2Ay%5E5%29 ALIGN=MIDDLE  ALT=\"pi%2A%282%5E2%2B4%2Asqrt%28xy%5E5%29%2Bx%2Ay%5E5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%284%2B4%2Ay%5E2%2Asqrt%28xy%29%2Bx%2Ay%5E5%29 ALIGN=MIDDLE  ALT=\"pi%2A%284%2B4%2Ay%5E2%2Asqrt%28xy%29%2Bx%2Ay%5E5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "In case of confusion in the final step, for the middle term,<BR>\n" );
document.write( "know that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28N%5E2%29=N ALIGN=MIDDLE  ALT=\"sqrt%28N%5E2%29=N\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Every TWO occurences of the same factor under the square root radical can be taken outside as a single occurence.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Asqrt%28x%2AY%5E5%29=4%2Asqrt%28x%2Ay%5E2%2Ay%5E2%2Ay%29 ALIGN=MIDDLE  ALT=\"4%2Asqrt%28x%2AY%5E5%29=4%2Asqrt%28x%2Ay%5E2%2Ay%5E2%2Ay%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Ay%2Ay%2Asqrt%28x%2Ay%29 ALIGN=MIDDLE  ALT=\"4%2Ay%2Ay%2Asqrt%28x%2Ay%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Ay%5E2%2Asqrt%28x%2Ay%29 ALIGN=MIDDLE  ALT=\"4%2Ay%5E2%2Asqrt%28x%2Ay%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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